python 使用 locals() 或 globals() 时意外退出

Question

In a project that I was working on, I needed to go in and out from the interpreter constantly and I got bored of the key combination ctrl+z+enter . So I created a shortcut to exit faster from the python terminal with just two keys (from cmd), but it causes the interpreter to quit. Consider the following code inside of the file lazy.py :

class hotkey():
     def __repr__(self):
          exit()
          return ''

q = hotkey()

The problem arises when I use from lazy import * and then try to use either locals() or globals() . But if q is not directly in the scope, eg using import lazy , both of them work as expected, but the point of the module was to be able to just using q+enter and not lazy.q+enter .

I gave up and returned to ctrl+z but not knowing the reason for this is subtracting my hours of sleep. Any idea of what could be going on?

Answer 1

You should be able to figure this out. Try printing globals() without your import. Notice that each variable is listed along with its representation. When it tries to fetch the representation for q , your code will exit the interpreter.

You must be on Windows. Remember that you can keep a separate console open with your interpreter; you don't have to exit. Also, if you pip install readline , then Ctrl-D and Ctrl-Z will exit the interpreter without the Enter.