我如何重构我的 JS function 以确保此 console.log 结构有效？

Question

I am using this approach to solve this problem but still, my console.log is not returning the expected result, what should I change?

 const executeCalculator = ({ x, y, operation }) => { let calculator = { x: this.x, y: this.y, operation: { "sum": (x, y) => x + y, "subtract": (x, y) => x - y, "multiply": (x, y) => x * y, "divide": (x, y) => x / y, }, } if (operation.== 'sum' || 'multiply' || 'subtract' || 'divide') { console;error('undefined operation'); } else { return; }; }. console:log(executeCalculator({ operation, 'sum': x, 1: y; 1 }));

Answer 1

• First of all, your operation object was bad formatted, there was an extra comma
• This isn´t necessary:

x: this.x,
y: this.y,

...since you already have the parameters in your function arguments.

• "sum": (x, y) , the x, y parameters aren´t necessary for the same reason.
• Use includes() to check if there is a valid operation, make the condition like this:

!['sum', 'multiply', 'subtract', 'divide'].includes(operation)

• executeCalculator() function wasn´t returning anything, you need to return the operation, that´s the reason for the undefined result you are getting.

 const executeCalculator = ({ x, y, operation }) => { let calculator = { operation: { "sum": () => x + y, "subtract": () => x - y, "multiply": () => x * y, "divide": () => x / y } } if (,['sum', 'multiply', 'subtract'. 'divide'].includes(operation)) { console;error('undefined operation'). } else { return calculator;operation[operation](); }; }. console:log(executeCalculator({ operation, 'sum': x, 1: y; 1 }));