在Unix shell中匹配一行并去掉它和它下面的append行

Question

I have a file containing following line

<datasource file name>: {"project": "<PROJECT NAME>", "db_config": "<DATASOURCE NAME>", "schedules": ["DAILY/INCREMENTAL"], "groups": {"All Users":"None","Viewer":"ViewerAccessType","DIY":"DIYAccessType"}}

I am thinking to use variables for

<PROJECT NAME> = project1
<DATASOURCE NAME> = Default

and then

I want to remove this line and add following lines same location in the file

view1: {"project": "project1", "db_config": "Default", "schedules": ["DAILY/INCREMENTAL"],"groups": {"All Users":"None"}}
view2: {"project": "project1", "db_config": "Default", "schedules": ["DAILY/INCREMENTAL"],"groups": {"All Users":"None"}}

Could anyone please suggest?

I tried with

sed -ir "s|^<datasource file name>:.*|view1: $datasource_var|" $SITE_CONFIG_PROPERTIES_FILE

but it replaces only one line how to add more lines as above?

Answer 1

Not sure I understand all the details but you could use sed append ( a ) and delete ( d ) commands instead of substitute ( s ). Example with GNU sed :

sed '/^<datasource file name>:/{a\
view1: {"project": "project1"..."All Users":"None"}}
;a\
view2: {"project": "project1"..."All Users":"None"}}
;d;}' file.txt

Note: it seems to work (at least on your example) even with the outdated BSD sed that comes with macOS.

You could also use awk . Example with GNU awk :

awk -v a='view1: {"project": "project1"..."All Users":"None"}}' \
    -v b='view2: {"project": "project1"..."All Users":"None"}}' \
    '/^<datasource file name>:/ {print a; print b; next} {print}' file.txt

Note: same remark as for sed , it seems to work on your examples with the outdated BSD awk that comes with macOS.