[英]clang on Windows / msvc: why under FE_UPWARD printf("%.1f\n", 0.0) prints 0.1 instead of 0.0?
Sample code (t928.c):示例代码(t928.c):
#include <stdio.h>
#include <fenv.h>
#if _MSC_VER && ! __clang__
#pragma fenv_access (on)
#else
#pragma STDC FENV_ACCESS ON
#endif
int main(void)
{
int i = fesetround( FE_UPWARD );
if ( ! i )
{
printf( "%.1f\n", 0.0 );
}
return 0;
}
Invocations:调用:
$ clang t928.c -Wall -Wextra -std=c11 -ffp-model=strict -pedantic && ./a.exe
0.1
$ cl t928.c /std:c11 /Za /fp:strict && ./t928.exe
0.1
Versions:版本:
$ clang --version
clang version 12.0.0
$ cl
Microsoft (R) C/C++ Optimizing Compiler Version 19.28.29913 for x64
UPD20210824. UPD20210824。 User chux - Reinstate Monica supposed:
用户 chux - 恢复莫妮卡假设:
Some compilers have trouble properly including FP support when there is no FP activity in user code.
当用户代码中没有 FP 活动时,某些编译器无法正确包含 FP 支持。 Try adding some.
尝试添加一些。
Here is it:就这个:
int main(void)
{
float f1 = 0.0f;
float f2 = 0.0f;
float f3 = 0.0f;
int i = fesetround(FE_UPWARD);
if ( ! i )
{
printf("%.1f\n", 0.0);
}
f3 = f1 + f2;
printf("%.1f\n", f3);
return 0;
}
Invocations:调用:
$ gcc t928.c -Wall -Wextra -std=c11 -pedantic && ./a.exe
t928.c:6: warning: ignoring '#pragma STDC FENV_ACCESS' [-Wunknown-pragmas]
6 | #pragma STDC FENV_ACCESS ON
|
0.0
0.0
$ cl t928.c /std:c11 /Za /fp:strict && ./t928.exe
0.1
0.1
$ clang12 t928.c -Wall -Wextra -std=c11 -ffp-model=strict -pedantic && ./a.exe
0.1
0.1
UPD20210831. UPD20210831。 Answer from Microsoft:
来自微软的回答:
This is an issue in the Universal CRT with our FE_UPWARD and FE_DOWNWARD rounding modes where some numbers will round up as though they had additional non-zero digits after them.
这是我们的 FE_UPWARD 和 FE_DOWNWARD 舍入模式中通用 CRT 中的一个问题,其中一些数字会舍入,就好像它们后面有额外的非零数字一样。 This will be fixed in the Universal CRT and will be included in a future release of the Windows OS and Windows SDK.
这将在通用 CRT 中修复,并将包含在 Windows 操作系统和 Windows SDK 的未来版本中。
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