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Google 表格脚本 - 遍历数组,查找仅包含文本和部分文本的数组项并替换整个项

[英]Google Sheets Script - Loop through array, find array items with only text and partial text and replace whole item

I have a code that is half working, the last thing I can't figure out is how to find an array item containing a number (eg 123) and some text (m/s) and replace this whole item with a completely blank array item: [] .我有一个半工作的代码,我最后想不通的是如何找到一个包含数字(例如 123)和一些文本(m/s)的数组项并将整个项替换为一个完全空白的数组项目: [] No number and no m/s.没有数字,也没有 m/s。

I am not familiar with most of the terminology and am a complete novice at this.我不熟悉大多数术语,并且在这方面完全是新手。 This is what I've got so far:这是我到目前为止所得到的:

function condForm() {
  var sh = ss.getSheetByName('Sheet1');
  var range = sh.getRange("D4:D20"); //*** for the sake of brevity setting to 20 instead of 154
  var values = range.getValues();  
  var row = [];
  var cols = values[0].length;

  for (var i = 0, l = values.length; i < l; i++)
  {
    row = values[i];
    for (var j = 0; j < cols; j++)
    {
      if (row[j] === 'TTK') { row[j] = ''; }
      if(typeof row[j] != "string") { continue; } // line to allow indexOf to work
      if (row[j].indexOf('m/s') > -1) { var newValue = row[j].replace('m/s', '') } //attempting to use indexOf to search for partial match to m/s, does not work but does not return error
    }
  }
Logger.log(values);
}

Without code the logger outputs [[400.0], [600.0], [600.0], [600.0], [], [1283 m/s], [TTK], [440.0], [661.0], [771.0], [771.0], [], [960m/s], [TTK], [381.0], [667.0], [667.0]]没有代码,记录器输出[[400.0], [600.0], [600.0], [600.0], [], [1283 m/s], [TTK], [440.0], [661.0], [771.0], [771.0], [], [960m/s], [TTK], [381.0], [667.0], [667.0]]

And with the code above the output becomes [[400.0], [600.0], [600.0], [600.0], [], [1283m/s], [], [440.0], [661.0], [771.0], [771.0], [], [960m/s], [], [381.0], [667.0], [667.0]] = same number of array items = great success使用上面的代码,output 变为[[400.0], [600.0], [600.0], [600.0], [], [1283m/s], [], [440.0], [661.0], [771.0], [771.0], [], [960m/s], [], [381.0], [667.0], [667.0]] = 相同数量的数组项 = 巨大成功

I attempted to use indexOf to search for any array items containing m/s.我试图使用indexOf来搜索任何包含m/s 的数组项。 It didn't work but also didn't return an error.它没有用,但也没有返回错误。 What's it doing?它在做什么? Am I on the right lines at all?我在正确的路线上吗?

I would like a way to turn [1283m/s] and [960m/s] into blanks: [] .我想要一种将[1283m/s][960m/s]变成空白的方法: []

Thank you for reading.感谢您的阅读。

My code was sourced from Max Makhrov: https://stackoverflow.com/a/47575871/1341041我的代码来自 Max Makhrov: https://stackoverflow.com/a/47575871/1341041

and from Andres Duarte : https://stackoverflow.com/a/60226151/1341041来自 Andres Duartehttps://stackoverflow.com/a/60226151/1341041

As far as I can tell you're changing the array row .据我所知,您正在更改数组row But you're never changing the array values .但是您永远不会更改数组values

Probably you need something like this in the middle:中间可能需要这样的东西:

...

if (row[j] === 'TTK') { values[i][j] = ''; }
if (typeof row[j] != "string") { continue; }
if (row[j].indexOf('m/s') > -1) { values[i][j] = row[j].replace('m/s', '') }

...

But actually for your purpose I'd propose to use the native tool TextFinder :但实际上出于您的目的,我建议使用本机工具TextFinder

function condForm() {
  const sheet = ss.getSheetByName('Sheet1');
  const range = sheet.getRange('D4:D20');
  // range.createTextFinder('m/s').replaceAllWith('');
  range.createTextFinder('.*m/s.*').useRegularExpression(true).replaceAllWith('');
  range.createTextFinder('^TTK$').useRegularExpression(true).replaceAllWith('');
}

https://developers.google.com/apps-script/reference/spreadsheet/text-finder https://developers.google.com/apps-script/reference/spreadsheet/text-finder

Just in case, if you really into the nested loops it as well can be done a bit cleaner this way:以防万一,如果你真的进入嵌套循环,它也可以通过这种方式做得更干净:

 var values = [[400], [600], [600], [600], [], ['1283 m/s'], ['TTK'], [440], [661], [771], [771], [], ['960m/s'], ['TTK'], [381], [667], [667]]; for (row in values) { for (col in values[row]) { if (values[row][col] == 'TTK') values[row][col] = ''; // values[row][col] = values[row][col].toString().replace(/\s*m\/s/g,''); values[row][col] = values[row][col].toString().replace(/.*m\/s.*/,''); } } console.log(values);

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