[英]C language not giving me the output in decimals
//Converts Farenheit tempretaure to into the celsius scale
#include <stdio.h>
#define FREEZING_PT 32.0f
#define FACTOR 5.0f/9.0f
int main(void)
{
float faren,c;
printf("Enter the Farenheit temperature: ");
scanf("%f",&faren);
float c = (faren - FREEZING_PT)*FACTOR;
printf("The required celsius tempreature is: %.1f\n", c);
return 0;
}
Im a Complete C beginner and this may be very elementary but I cannot figure out the problem here.我是一个完整的 C 初学者,这可能是非常初级的,但我无法弄清楚这里的问题。
In the above code, the value I get returned is always the Celsius temperature in integer values, even if it is a float type.在上面的代码中,我返回的值始终是 integer 值中的摄氏温度,即使它是 float 类型。 For example, if the Fahrenheit temperature was 0°, the result in Celsius should be -17.7°, but I get the result only as -17°.例如,如果华氏温度为 0°,则摄氏温度的结果应为 -17.7°,但我得到的结果仅为 -17°。
Edited code:编辑代码:
//Converts Farenheit tempretaure to into the celsius scale
#include <stdio.h>
#define FREEZING_PT 32.0f
#define FACTOR 5.0f/9.0f
int main(void)
{
float faren,c;
printf("Enter the Farenheit temperature: ");
scanf("%f",&faren);
c = (faren - FREEZING_PT)*FACTOR;
printf("The required celsius tempreature is: %.1f\n", c);
return 0;
}
In your code, you've declared the variable 'c' twice.在您的代码中,您已两次声明变量“c”。 After removing the first declaration of the variable 'c', it's working properly.删除变量“c”的第一个声明后,它可以正常工作。
I'm getting the correct output.我得到正确的 output。
Enter the Farenheit temperature: 0输入华氏温度:0
The required celsius tempreature is: -17.8所需摄氏温度为:-17.8
Enter the Farenheit temperature: 1输入华氏温度:1
The required celsius tempreature is: -17.2所需摄氏温度为:-17.2
Enter the Farenheit temperature: 2输入华氏温度:2
The required celsius tempreature is: -16.7所需摄氏温度为:-16.7
Remove the first declaration of the variable 'c'.删除变量“c”的第一个声明。 It should work.它应该工作。
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