[英]Hibernate composite key mapping issue
I'm trying to map entities of the same class (MyData) to each other through a mapping table. 我正在尝试通过映射表将相同类(MyData)的实体相互映射。 MyData has a composite primary key (id1 and id2).
MyData具有复合主键(id1和id2)。 When I create the class (see below), it seems like Hibernate is reversing the order of the FK mappings (ie a_id1 is pointing to b_id2, etc...).
当我创建类时(见下文),似乎Hibernate正在反转FK映射的顺序(即a_id1指向b_id2,等等。。。)。 This does not seem right.
这似乎不正确。 Does the inverseJoinColumns have to be the opposite order of joinColums?
inverseJoinColumns是否必须与joinColums的顺序相反? I couldn't find many examples online with composite keys...
我在网上找不到很多带有复合键的示例...
public class MyData {
// has composite key (id1, id2)
// ... //
@ManyToMany
@Cascade(org.hibernate.annotations.CascadeType.SAVE_UPDATE)
@JoinTable(name = "MyData_foo",
joinColumns = {
@JoinColumn(name = "a_id1"),
@JoinColumn(name = "a_id2")
},
inverseJoinColumns = {
@JoinColumn(name = "b_id1"),
@JoinColumn(name = "b_id2") })
)
private Set<MyData> mySet = new HashSet<MyData>();
// ... //
}
CREATE TABLE `MyData_foo` (
`b_id2` bigint(20) NOT NULL default '0',
`b_id1` bigint(20) NOT NULL default '0',
`a_id2` bigint(20) NOT NULL default '0',
`a_id1` bigint(20) NOT NULL default '0',
PRIMARY KEY (`a_id1`,`a_id2`,`b_id1`,`b_id2`),
KEY `FKCD44188BB2B7A1BE` (`b_id1`,`b_id2`),
KEY `FKCD44188B7997E326` (`a_id1`,`a_id2`),
CONSTRAINT `FKCD44188B7997E326` FOREIGN KEY (`a_id1`, `a_id2`) REFERENCES `MyData` (`b_id2`, `b_id1`),
CONSTRAINT `FKCD44188BB2B7A1BE` FOREIGN KEY (`b_id1`, `b_id2`) REFERENCES `MyData` (`a_id2`, `a_id1`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;
Your mapping is wrong. 您的映射错误。 You need to add "referencedColumnName" to all of your JoinColumn annotations, eg
您需要在所有JoinColumn批注中添加“ referencedColumnName”,例如
@JoinTable(name = "MyData_foo",
joinColumns = {
@JoinColumn(name = "a_id1", referencedColumnName = "id1"),
@JoinColumn(name = "a_id2", referencedColumnName = "id2")
},
inverseJoinColumns = {
@JoinColumn(name = "b_id1", referencedColumnName = "id1"),
@JoinColumn(name = "b_id2", referencedColumnName = "id2")
})
)
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