如何在Django中过滤多对多关系中的不同对象？

Question

I have a page where I show all workout plans from each user. But I want to show only one entry per user, so then I can click and get all workouts plans of that user. So, instead of showing:

User 1 - Day 1
USer 1 - Day 2
User 2 - Day 1
USer 2 - Day 2

I want to show:

User 1
User 2

I was using the following view:

planos = Workout.objects.all()

But this would show everything, so I tried:

plan = Workout.objects.values('member').distinct()

But this returns {'member': 1} and {'member': 2} .

How can I access the name of the user?

class Member(models.Model):
    user = models.OneToOneField(User, on_delete=models.CASCADE)
    socio = models.CharField(max_length=6)
    address = models.CharField(max_length=200)
    city = models.CharField(max_length=200)
    

class Exercise(models.Model):
    exercise = models.CharField(max_length=166)
    series = models.CharField(max_length=2)
    reps = models.CharField(max_length=2)
    maquina = models.ForeignKey(Maquina)


class Workout(models.Model):
    member = models.ForeignKey(Membro)
    day = models.CharField(max_length=1)
    exercises = models.ManyToManyField(Exercise)

Answer 1

You filter on the Member model:

Member.objects.filter(
    
)

This will make a LEFT OUTER JOIN on the Workout model, and thus retrieve Member s if (and only if) there is at least one related Workout object. The .distinct() will prevent that the same Member is returned multiple times.

We can also obtain the User models behind that member with:

User.objects.filter(
    
)

If you simply want to retrieve all members, you can work with Member and thus render these, and then ensure that one can click a link to get details for that Member .