即使我在联合中使用指针，为什么联合的大小不是 8 个字节而是 4 个字节？

Question

union one
{
    int *ui;
    int u;
        
} yoo;

void main() 
{
    printf("%d\m", sizeof(yoo))
}

Why is the sizeof union not 8 bytes but 4 bytes even if I am using pointer in my union?

I am using a 64 bit machine.

Answer 1

Its because you have compiled it as 32-bit executable.