如何输入一个数字x并打印x次，每次增加2

Question

I need to take number x as input and print the first x odd numbers. If input 8 was given, the output would be: 1 3 5 7 9 11 13 15.

Answer 1

x = int(input('Enter your number:'))
for i in range(2*x):
    if i % 2 == 1:
        print(i)

Answer 2

Here is a solution without loop. It uses range to get directly the even numbers, converts those integers to string and displays them all at once using newlines as separator:

n = int(input('Enter your number:'))
print('\n'.join(map(str,range(1,2*n,2))))

output for 8 as input:

1
3
5
7
9
11
13
15