如何在浏览器中使用内联源代码 map 评估代码以获得适当的异常堆栈？

Question

Here is a code with inlined source map:这是带有内联源代码 map 的代码：

let b = 'sws';\r\nlet f = 'zzz';\r\nconsole.log('wow');\r\nfunction ff() {\r\n    console.log('wwwww');\r\n    return 'WEEE'.tr();\r\n}\r\nconsole.log(ff());\r\n//# sourceMappingURL=data:application/json;base64,eyJ2ZXJzaW9uIjozLCJmaWxlIjoidGVzdC5qcyIsInNvdXJjZVJvb3QiOiIiLCJzb3VyY2VzIjpbInRlc3QudHMiXSwibmFtZXMiOltdLCJtYXBwaW5ncyI6IkFBQUEsSUFBSSxDQUFDLEdBQUcsS0FBSyxDQUFDO0FBQ2QsSUFBSSxDQUFDLEdBQUcsS0FBSyxDQUFDO0FBQ2QsT0FBTyxDQUFDLEdBQUcsQ0FBQyxLQUFLLENBQUMsQ0FBQTtBQUVsQixTQUFTLEVBQUU7SUFDUCxPQUFPLENBQUMsR0FBRyxDQUFDLE9BQU8sQ0FBQyxDQUFBO0lBQ3BCLE9BQU8sTUFBTSxDQUFDLEVBQUUsRUFBRSxDQUFDO0FBQ3ZCLENBQUM7QUFDRCxPQUFPLENBQUMsR0FBRyxDQUFDLEVBQUUsRUFBRSxDQUFDLENBQUEifQ=="

if I simply do an eval for that code I'll get an exception but without an aligned source map. Is there a way to fix that?如果我只是对该代码进行评估，我将得到一个异常，但没有对齐源 map。有没有办法解决这个问题？

Answer 1

sourceMappingURL seems deprecated. sourceMappingURL 似乎已弃用。 Have you tried with sourceURL instead?您是否尝试过使用sourceURL ？

如何在浏览器中使用内联源代码 map 评估代码以获得适当的异常堆栈？

问题描述

1 个解决方案

解决方案1
0 2021-09-26 19:50:14

如何在浏览器中使用内联源代码 map 评估代码以获得适当的异常堆栈？

问题描述

1 个解决方案

解决方案1 0 2021-09-26 19:50:14

解决方案1
0 2021-09-26 19:50:14