[英]How do I get a laravel many to many relationship
I have a many-to-many relationship between a Post model and Category model in a my laravel blog project.我的 laravel 博客项目中的帖子 model 和类别 model 之间存在多对多关系。 And I'm trying to get posts that has a particular category id like so
我正在尝试获取具有特定类别 ID 的帖子,就像这样
public function categoryPosts($category_id)
{
$posts = Post::whereHas('categories' , function($cat) use($category_id){
$cat->where('id' , $category_id);
})->get();
}
And the route to this controller for the query is this查询到这个 controller 的路由是这样的
Route::get('/view/categories/posts/{category_id}' , [CategoryController::class , 'categoryPosts'])->name('category.posts');
And I'm getting an exception我遇到了一个例外
Illuminate\Database\QueryException
SQLSTATE[23000]: Integrity constraint violation: 1052 Column 'id' in where clause is ambiguous (SQL: select * from `posts` where exists (select * from `categories` inner join `category_post` on `categories`.`id` = `category_post`.`category_id` where `posts`.`id` = `category_post`.`post_id` and `id` in (2)))
<?php
namespace App\Models;
use Illuminate\Database\Eloquent\Factories\HasFactory;
use Illuminate\Database\Eloquent\Model;
class Post extends Model
{
use HasFactory;
protected $guarded = [];
public function categories(){
return $this->belongsToMany(Category::class);
}
}
Here is the category model这是类别 model
<?php
namespace App\Models;
use Illuminate\Database\Eloquent\Factories\HasFactory;
use Illuminate\Database\Eloquent\Model;
class Category extends Model
{
use HasFactory;
protected $fillable = ['name'];
public function posts(){
return $this->belongsToMany(Post::class);
}
}
here are the migrations这是迁移
public function up()
{
Schema::create('categories', function (Blueprint $table) {
$table->id();
$table->string('name')->unique();
$table->timestamps();
});
}
public function up()
{
Schema::create('posts', function (Blueprint $table) {
$table->id();
$table->string('title')->unique();
$table->string('image_path');
$table->string('slug');
$table->text('content');
$table->timestamps();
});
}
public function up()
{
Schema::create('category_post', function (Blueprint $table) {
$table->id();
$table->foreignId('category_id')->constrained();
$table->foreignId('post_id')->constrained();
$table->timestamps();
});
}
You need to change where condition.您需要更改 where 条件。
From从
$cat->where('id' , $category_id);
to到
$cat->where('categories.id' , $category_id);
Make another table with post and categories relationship, like this:制作另一个具有帖子和类别关系的表,如下所示:
Schema::create('posts_post_categories', function (Blueprint $table) {
$table->increments('id');
$table->integer('post_categories_id')->unsigned();
$table->foreign('post_categories_id')->references('id')->on('post_categories');
$table->integer('post_id')->unsigned();
$table->foreign('post_id')->references('id')->on('posts');
$table->softDeletes();
});
In model Post在 model 发帖
public function category()
{
return $this->belongsToMany(PostCategory::class, 'posts_post_categories', 'post_id', 'post_categories_id');
}
In model category在 model 类别中
public function posts()
{
return $this->belongsToMany(Post::class,'posts_post_categories', 'post_categories_id', 'post_id');
}
In controller to get posts, by example在controller获取帖子,以实例为例
public function showCategory($url){
$category = PostCategory::where('url',$url)->first();
$posts = $category->posts()->paginate(7);
$recentsPosts = Post::orderBy('created_at','Desc')->take(5)->get();
$categories = PostCategory::all();
return view('site.blog.category.index', compact('posts','categories','recentsPosts','category'));
}
Without using this不使用这个
$posts = Post::whereHas('categories' , function($cat) use($category_id){
$cat->where('id' , $category_id);
})->get();
you can use just你可以只使用
$category = Category::with('posts')->where("id", $category_id);
$posts = $catetory->exists() ? $category->first()->posts : [];
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