简体   繁体   English

用于替换字符串中间字符的正则表达式

[英]Regular expression to replace middle chars of a string

I would like to replace middle 4 characters of a string with ****我想用 **** 替换字符串的中间 4 个字符

For example: ABCDEFG should become AB****G例如:ABCDEFG 应该变成 AB****G

Please suggest a Regex to achieve this.请建议一个正则表达式来实现这一点。

Note: The length of the string is always same.注意:字符串的长度始终相同。

Found the solution that I was looking for:找到了我正在寻找的解决方案:

var s="ABCDEFG" var s="ABCDEFG"
var reg=/\b(\w{2})\w+(\w)\b/g var reg=/\b(\w{2})\w+(\w)\b/g

s.replace(reg, '$1**$2'); s.replace(reg, '$1**$2');

output: AB****G output:AB****G

This will replace all the middle chars except first 2 and last 1 char in a string.这将替换字符串中除了前 2 个和最后 1 个字符之外的所有中间字符。

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM