从列表中创建一个键等于值的字典

Question

my pourpose is to create a dictionary starting from a list, where the keys are equal to the values. What I have done till now is:

dicts = {}
keys = range(len(x))
values = x
for i in keys:
    dicts[i] = values[i]

the output is:

{0: 'a', 1: 'b', 2: 'c'}

what I want is:

{a: 'a', b: 'b', c: 'c'}

I don't know how modify the keys. Thanks you all.

Answer 1

You can try this:

dicts[values[i]] = values[i]

Answer 2

Try:

dict(zip(values, values))

Answer 3

The problem is in your last line Your saying: dicts[i] = values[i] instead put: dicts[values[i]] = values[i] Cause i is the index not the item in the list

and don't forget to define x first: x = ['a','b','c']

this will output:

{'a': 'a', 'b': 'b', 'c': 'c'}

Answer 4

You can use dict comprehension

values = ['a','b','c']
d = {v:v for v in values}

Answer 5

You can use the dict function on zipping the list twice:

x = ['a', 'b', 'c']
dict(zip(*[x]*2))

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{'a': 'a', 'b': 'b', 'c': 'c'}