计算 python 中列表中每个元素的单词出现次数

Question

I have a code which gives me count of strings in a list.

names=['Deepak is a boy','Reema is short','John is tall','Deepak is shy','Munna is naughty','Reema','Deepak is shy','Amit is hilarious','John is tall','Reema is short']

nm=input('Enter the word you want to count: ')
count=names.count(nm)
print('count = ', count)

Output:

Enter the word you want to count: John is tall
count =  2

However I want to find occurences of a single word for ex:shy. If I type shy then I get count as zero. Can someone help me with how to get count of individual words. Expected output for word shy:

[0, 0, 0, 1, 0, 0, 1, 0, 0, 0]

Answer 1

names=['Deepak is a boy','Reema is short','John is tall','Deepak is shy','Munna is naughty','Reema','Deepak is shy','Amit is hilarious','John is tall','Reema is short']
nm=input('Enter the word you want to count: ')
occurences = [name.count(nm) for name in names]
count = sum(occurences) # This gives total number of occurences
print(occurences) # This will print out all occurences of input string
print('count = ', count) # This prints total number of occurences, although not requested may become useful for you.

This answer will allow for if names occurrences is not == 1 but greater as suggested in comments..

Answer 2

You can loop through the list and count occurences for each text in names .

c = []
for name in names:
    c.append(name.count(nm))