找到循环中的最高数字

Question

I have a loop that repeats itself 100 times and every time it generates a number from 34.5 to 42.0

Random rnd = new Random();
const double MAX = 42.0;
const double MIN = 34.5;
//Console.WriteLine("{0:f1}",num);
for (int i = 0; i < 100; i++)
{
  double num = rnd.NextDouble() * (MAX - MIN) + MIN;
  Console.WriteLine("{0:f1}", num);
}

and I want to find the highest number and print it but I don't know how to find the number

Answer 1

You can store your values to a List and then find the max and min values

Random rnd = new Random();
const double MAX = 42.0;
const double MIN = 34.5;
//Console.WriteLine("{0:f1}",num);
List<double> lst = new List<double>(100);
for (int i = 0; i < 100; i++)
{       
   double num = rnd.NextDouble() * (MAX - MIN) + MIN;
   lst.Add(num);
   Console.WriteLine("{0:f1}", num);
}
Console.WriteLine("max number is " + lst.Max().ToString());

Answer 2

Here's the simplest change to your existing code:

Random rnd = new Random();
const double MAX = 42.0;
const double MIN = 34.5;
//Console.WriteLine("{0:f1}",num);
double max = double.MinValue;
for (int i = 0; i < 100; i++)
{
    double num = rnd.NextDouble() * (MAX - MIN) + MIN;
    max = num > max ? num : max;
}
Console.WriteLine("{0:f1}", max);

Answer 3

Create a variable outside the loop, and then set that to the minimum possible value. Then on each iteration, if the generated number is larger than that, store the generated number. Then after the loop you can print it out.

Random rnd = new Random();
const double MAX = 42.0;
const double MIN = 34.5;
double highestRandom = MIN;
//Console.WriteLine("{0:f1}",num);
for (int i = 0; i < 100; i++)
{
    double num = rnd.NextDouble() * (MAX - MIN) + MIN;
    if (num > highestRandom)
    {
        highestRandom = num;
    }

    Console.WriteLine("{0:f1}", num);
}

Console.WriteLine("The highest number was: {0:f1}", highestRandom);

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