如何使用正则表达式查找字符超过 1 次？

Question

import re
palabra="hola mundo"
caracter="o"
buscacaracter=(re.search(caracter,palabra))
print(buscacaracter)

So in this code it search until the first "o" is found but it doesn't count the last "o".

Is there a way to find every "o"?

This happens with these methods as well:

print(buscacaracter.start())
print(buscacaracter.end())
print(buscacaracter.span())

And when I use this method:

(re.findall(caracter,palabra))

it doesn't return the positions of the "o", just the number of them.

Answer 1

If you just want the index of each caracter it is faster, easier to use enumerate :

palabra="hola mundo"
caracter="o"
>>> [i for i,c in enumerate(palabra) if c==caracter]
[1, 9]

If you want a regex, use finditer which return a match object which contains the index:

>>> [m.span()[0] for m in re.finditer(rf'{caracter}', palabra)]
[1, 9]