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postgres 中具有多个值列的数据透视表

[英]pivot table with multiple value columns in postgres

I need a query which will help me to get data as described below我需要一个查询来帮助我获取如下所述的数据

I have a table as followed我有一张桌子如下

ID ID date日期 STATUS地位 TIME09_10 TIME09_10 TIME10_11 TIME10_11 TIME11_12 TIME11_12 TIME12_13 TIME12_13
1 1 2021-09-01 2021-09-01 RUN 30 30 60 60 45 45 0 0
2 2 2021-09-01 2021-09-01 WALK 15 15 0 0 o 30 30
3 3 2021-09-01 2021-09-01 STOP停止 15 15 0 0 15 15 30 30

I want this data to be in below format.我希望这些数据采用以下格式。 From the above table , value columns name has to be replaced with hour and join with date column.从上表中,值列名称必须替换为小时并与日期列连接。 I would really appreciate someone's help.我真的很感激有人的帮助。 I am using postgres sql database.我正在使用 postgres sql 数据库。

date & time约会时间 run walk stop停止
2021-09-01 09:00 2021-09-01 09:00 30 30 15 15 15 15
2021-09-01 10:00 2021-09-01 10:00 60 60 0 0 0 0
2021-09-01 11:00 2021-09-01 11:00 45 45 0 0 15 15
2021-09-01 12:00 2021-09-01 12:00 0 0 30 30 30 30

You can use the crosstab(source_sql text, category_sql text) function.您可以使用crosstab(source_sql text, category_sql text)函数。 You need to install the tablefunc extension:您需要安装tablefunc扩展:

create extension if not exists tablefunc;

Read about the extension in the documentation.阅读文档中的扩展

The function expects data in the three-column format (row_name, category, value) .该函数需要三列格式(row_name, category, value) In this case they are date+time , status and duration .在这种情况下,它们是date+timestatusduration

select 
    date+ '8 hour'::interval+ '1 hour'::interval* i as hour,
    status,
    (array[time09_10, time10_11, time11_12, time12_13])[i] as duration
from my_table
cross join generate_series(1, 4) i

        hour         | status | duration
---------------------+--------+----------
 2021-09-01 09:00:00 | RUN    |       30
 2021-09-01 09:00:00 | WALK   |       15
 2021-09-01 09:00:00 | STOP   |       15
 2021-09-01 10:00:00 | RUN    |       60
 2021-09-01 10:00:00 | WALK   |        0
 2021-09-01 10:00:00 | STOP   |        0
 2021-09-01 11:00:00 | RUN    |       45
 2021-09-01 11:00:00 | WALK   |        0
 2021-09-01 11:00:00 | STOP   |       15
 2021-09-01 12:00:00 | RUN    |        0
 2021-09-01 12:00:00 | WALK   |       30
 2021-09-01 12:00:00 | STOP   |       30
(12 rows)

Pass the query as the first argument to the function:将查询作为第一个参数传递给函数:

select *
from crosstab(
    $source$
        select 
            date+ '8 hour'::interval+ '1 hour'::interval* i as hour,
            status,
            (array[time09_10, time10_11, time11_12, time12_13])[i] as duration
        from my_table
        cross join generate_series(1, 4) i
    $source$,
    $category$
        values('RUN'), ('STOP'), ('WALK')
    $category$
) as (hour timestamp, run int, stop int, walk int)
        hour         | run | stop | walk
---------------------+-----+------+------
 2021-09-01 09:00:00 |  30 |   15 |   15
 2021-09-01 10:00:00 |  60 |    0 |    0
 2021-09-01 11:00:00 |  45 |   15 |    0
 2021-09-01 12:00:00 |   0 |   30 |   30
(4 rows)

There is a nice alternative if you do not want to use the extension.如果您不想使用扩展程序,还有一个不错的选择。 Convert the first query results to the expected output with the jsonb function:使用jsonb函数将第一个查询结果转换为预期输出:

select 
    hour, 
    (activities->>'RUN')::int as run,
    (activities->>'STOP')::int as stop,
    (activities->>'WALK')::int as walk
from (
    select hour, jsonb_object_agg(status, duration) as activities
    from (
        select 
            date+ '8 hour'::interval+ '1 hour'::interval* i as hour,
            status,
            (array[time09_10, time10_11, time11_12, time12_13])[i] as duration
        from my_table
        cross join generate_series(1, 4) i
        ) s
    group by hour
    ) s
order by hour

Test the jsonb solution in Db<>fiddle.Db<>fiddle 中测试jsonb解决方案

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