Pandas - 如果列中的 X 浮点数大于 Y，则找出 X 和 Y 之间的差值并乘以 0.25

Question

I suspect the solution is quite simple, but I have been unable to figure it out. Essentially, what I want to do is to query a column with the float object type to see if each value >= 100.00. If it is greater, then I want to take the value x and do so: ((x - 100)*.25)+100 = new value (replace original values inplace, preferably.)

The data looks something like:

Some columns here	A percentage stored as float
foobar	84.85
foobar	15.95
fuubahr	102.25

The result of the above operation mentioned would give the following for the above:

Some columns here	A percentage stored as float
foobar	84.85
foobar	15.95
fuubahr	100.5625

Thanks!

Answer 1

List comprehension is easy solution for this:

dataframe["A percentage stored as float"] = [((x - 100)*.25) + 100 if x >= 100 else x for x in dataframe["A percentage stored as float"]]

What it does: It loops through the each column row, checks if value meets our if stement and then does the applies the calculation, if statement is not met, then it returns the original row value.