Seaborn 无法覆盖 Matplotlib 的 rcParams['grid.linewidth']

Question

When I am trying to set the grid of a 3D plot using seaborn, such as

import matplotlib.pyplot as plt
import seaborn as sns
sns.set_style("white",{"grid.color": "0.2", "grid.linestyle": "-","grid.linewidth": "2"})
fig = plt.figure(figsize=(12,8))
ax = plt.axes(projection='3d')
plt.show()

The parameter "grid.linewidth" does not have any affect on the grid linewidth, however, if I add

  plt.rcParams['grid.linewidth'] = 2

before I set the figure, then I am able to change the grid thickness. Would anyone be able to explain how to incorporate that into the seaborn function or what I'm doing wrong? It does not matter where I place the rcParam inside the function.

Here is the output regardless of whether I put "2" or "200".

Answer 1

You can use set_context for this.

import matplotlib.pyplot as plt
import seaborn as sns
from mpl_toolkits.mplot3d import Axes3D

sns.set_style("white", {'grid.color': "0.2", "grid.linestyle": "--"})
sns.set_context("notebook", rc={"grid.linewidth": 3})
fig = plt.figure(figsize=(12,8))
ax = plt.axes(projection='3d')
plt.show()

set_style and set_context have these differing explanations for their rc dict, below.

This answer covers the difference in further detail.

<set_style>
rc : dict, optional
    Parameter mappings to override the values in the preset seaborn
    style dictionaries. This only updates parameters that are
    considered part of the style definition.

<set_context>
rc : dict, optional
    Parameter mappings to override the values in the preset seaborn
    context dictionaries. This only updates parameters that are
    considered part of the context definition.