如何在bash中使用POSIX找到不寻常的字符'？

Question

here are some names:

El Peulo'Pasa, Van O'Driscoll, Mike_Willam

how to filter the name contains ', using POSIX in bash by command find?

if I use the following command,

find . -maxdepth 1 -mindepth 1 -type d -regex '^.*[']*$' -print

Bash runs into a problem because the syntax ' will automatically convert the input to string

Answer 1

You don't need -regex ( which is a non-POSIX action ) for this at all; -name is more than adequate. ( -mindepth and -maxdepth are also extensions that aren't present in the POSIX standard).

To make a ' literal, put it inside double quotes, or in an unquoted context and precede it with a backslash:

find . -maxdepth 1 -mindepth 1 -type d -name "*'*" -print

...or the 100% identical but harder-to-read command line...

find . -maxdepth 1 -mindepth 1 -type d -name '*'\''*' -print

Answer 2

If you're just searching the current directory (and not its subdirectories), you don't even need find , just a wildcard ("glob") expression:

ls *\'*

(Note that the ' must be escaped or double-quoted, but the asterisks must not be.)

If you want to do operations on these files, you can either use that wildcard expression directly:

dosomethingwith *\'*
# or
for file in *\'*; do
    dosomethingwith "$file"
done

...or store the filenames in an array, then use that. This involves getting the quoting just right, to avoid trouble with other weird characters in filenames (eg spaces):

filelist=( *\'* )
dosomethingwith "${filelist[@]}"
# or
for file in "${filelist[@]}"; do
    dosomethingwith "$file"
done