如何根据深度嵌套的键对嵌套字典列表进行排序？
[英]How to sort a list of nested dictionaries based on a deeply nested key?
问题描述
I have a list that looks like this:
我有一个看起来像这样的列表：
ls = [
{
"max_supply": None,
"platform": None,
"quote": {
"USD": {
"fully_diluted_market_cap": 464800388135.72,
"last_updated": "2021-10-20T13:37:02.000Z",
"market_cap": 464800388135.7246,
"price": 3938.871641392752,
"volume_24h": 15411634916.820467,
"volume_change_24h": -3.4909
}
}
},
{
"max_supply": None,
"platform": None,
"quote": {
"USD": {
"fully_diluted_market_cap": 58764548678.52,
"last_updated": "2021-10-20T13:37:03.000Z",
"market_cap": 58764548678.52,
"price": 4784.77,
"volume_24h": 189992412916.647,
"volume_change_24h": 85.422
}
}
},
]
How do I order the given list by each market_cap value that is located in the quote and USD keys?如何按位于quote和USD键中的每个市场market_cap值对给定列表进行market_cap ？
I have found some solutions but they are only referring to sort by the first-level dictionary keys and values, however I have not been able to find any solutions for sorting by the keys and values in a dictionary two-level deep.我找到了一些解决方案，但它们仅指按一级字典键和值排序，但是我无法找到按两级深度字典中的键和值排序的任何解决方案。 in the given list.在给定的列表中。
2 个解决方案
解决方案1
1 已采纳 2021-10-20 13:52:51
You can pass a lambda function as the key argument for the built-in sorted function:您可以传递一个 lambda 函数作为内置sorted函数的key参数：
ls = [
{
"max_supply": None,
"platform": None,
"quote": {
"USD": {
"fully_diluted_market_cap": 464800388135.72,
"last_updated": "2021-10-20T13:37:02.000Z",
"market_cap": 464800388135.7246,
"price": 3938.871641392752,
"volume_24h": 15411634916.820467,
"volume_change_24h": -3.4909
}
}
},
{
"max_supply": None,
"platform": None,
"quote": {
"USD": {
"fully_diluted_market_cap": 58764548678.52,
"last_updated": "2021-10-20T13:37:03.000Z",
"market_cap": 58764548678.52,
"price": 4784.77,
"volume_24h": 189992412916.647,
"volume_change_24h": 85.422
}
}
},
]
sorted_ls = sorted(ls, key=lambda obj: obj["quote"]["USD"]["market_cap"])
Alternatively, you can use the .sort() method if you want to edit the list in-place.或者，如果您想就地编辑列表，您可以使用.sort()方法。
解决方案2
1 2021-10-20 13:52:53
You can define your own function that returns a key to sort against and then use sort like so您可以定义自己的函数，该函数返回要排序的键，然后像这样使用sort
all_data = [
{
"max_supply": null,
"platform": null,
"quote": {
"USD": {
"fully_diluted_market_cap": 464800388135.72,
"last_updated": "2021-10-20T13:37:02.000Z",
"market_cap": 464800388135.7246,
"price": 3938.871641392752,
"volume_24h": 15411634916.820467,
"volume_change_24h": -3.4909
}
}
},
{
"max_supply": null,
"platform": null,
"quote": {
"USD": {
"fully_diluted_market_cap": 58764548678.52,
"last_updated": "2021-10-20T13:37:03.000Z",
"market_cap": 58764548678.52,
"price": 4784.77,
"volume_24h": 189992412916.647,
"volume_change_24h": 85.422
}
}
},
]
def get_sort_key(current_dict):
return current_dict['quote']['USD']['market_cap']
all_data.sort(key=get_sort_key)
print(f'Sorted dict: {all_data}')
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