[英]Python: Difference in dates (column of dates vs. variable date)
I have a column of various dates and wanted to add another column to the dataframe that shows the difference between the dates in the column versus a date in various that I have set.我有一列不同的日期,并想向数据框中添加另一列,以显示该列中的日期与我设置的各种日期之间的差异。
enddate = date(2021, 10, 15)
Would something like:会喜欢:
I tried below but did returns error:我在下面尝试过,但确实返回错误:
from dateutil.relativedelta import relativedelta
metric_df['term'] = relativedelta(metric_df['maturity'], enddate).years
ValueError: The truth value of a Series is ambiguous. Use a.empty, a.bool(), a.item(), a.any() or a.all().
relativedelta
doesn't give you fractional years afaik, but you can easily calculate them yourself: relativedelta
不会给你小数年 afaik,但你可以很容易地自己计算它们:
import pandas as pd
# dummy data
metric_df = pd.DataFrame({'maturity': ["9/22/2025", "11/10/2033", "3/1/2023"]})
# convert to datetime, so we can run calculations with date & time
metric_df['maturity'] = pd.to_datetime(metric_df['maturity'])
# to get fractional years, we calculate difference in days and divide
# by the average number of days per year:
metric_df['term'] = (metric_df['maturity'] -
pd.Timestamp("2021-10-15")).dt.days / 365.25
metric_df['term']
0 3.937029
1 12.071184
2 1.374401
Name: term, dtype: float64
Have you considered using datetime subtraction?您是否考虑过使用日期时间减法? If I have two dates or datetimes, I can subtract them to yield a timedelta
object, ie如果我有两个日期或日期时间,我可以减去它们以产生一个timedelta
对象,即
start_date = date(2021,01,01)
end_date = date(2021,01,03)
delta = end_date - start_date
print(delta.days) # Should print 2
You can do this with columns too, yielding a column of timedelta
objects.您也可以对列执行此操作,生成一列timedelta
对象。
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