[英]Python - Ordering a dictionary with the array from file
I have been trying to fetch the last and first field from the /etc/passwd file in linux.我一直在尝试从 linux 中的/etc/passwd文件中获取最后一个和第一个字段。 I want to fetch the last fields of the file( the shell which users are using ) and the first field( number of users using the shell ) and add it to a list.
我想获取文件的最后一个字段(用户正在使用的外壳)和第一个字段(使用外壳的用户数)并将其添加到列表中。 For eg my final output must be something like
例如,我的最终输出必须类似于
{"/bin/bash/:[username1,username2],"/usr/sbin/nologin": [username2]}
Basically I want the key of the dictionary to be the shell and its value must be an array of users.基本上我希望字典的键是 shell,它的值必须是一个用户数组。
For this I have tried the below code为此,我尝试了以下代码
password_file = '/etc/passwd'
handler = open(password_file)
empty_dict = {}
for line in handler:
last_line = line.split(':')[6] #to fetch last line
first_line = line.split(':')[0] #to fetch first line
userlist[] #create an array for users
userlist.append(first_line)
if(first_line not in last_line):
empty_dict[last_line] = userlist #adding the user array to the dict as value
print(empty_dict)
This gives the output but this doesn't involve all the users to the dictionary key.这给出了输出,但这并不涉及字典键的所有用户。 Can you guys help me on which logic I went wrong.
你们能帮我解决我出错的逻辑吗? Any help would be great.
任何帮助都会很棒。 Thank you
谢谢
If I understood your question correctly, you're resetting the userlist
inside the loop.如果我理解正确你的问题,你重新设置
userlist
内循环。 Here is one possible way of doing this:这是执行此操作的一种可能方法:
from collections import defaultdict
password_file = '/etc/passwd'
handler = open(password_file)
userlist = defaultdict(list)
for line in handler:
first, *_, last = line.strip().split(':')
if first not in last:
userlist[last or 'nologin'].append(first)
handler.close()
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