类型错误：read_csv() 需要 0 到 1 个位置参数，但给出了 2 个

Question

What am I missing here? I have tried looking at the code but I do not know where the extra positional argument is located at,

def read_csv(path: str = None) -> List[List] :
    lead = Path(__file__).parent / f'../data/{path}'
    entries = []

    print('Reading dataset...')
    with open(lead, 'r') as csvfile:
        video_reader = csv.reader(csvfile)
        for row in video_reader:
            entries.append(row)

    return print(entries)

Traceback (most recent call last):
    File "C:/Users/MEDIAMARKT/Desktop/booking/__main__.py", line 15, in <module>
        gui = GUI()
      File "C:\Users\MEDIAMARKT\Desktop\booking\gui.py", line 22, in init
          self.upload_data()
        File "C:\Users\MEDIAMARKT\Desktop\booking\gui.py", line 84, in upload_data
            self.booking.read_csv(path)
          TypeError: read_csv() takes from 0 to 1 positional arguments but 2 were given

Answer 1

Your error is elsewhere, not in the snippet provided, since as a standalone function, that code should work fine.

Looking at your traceback, you've introduced classes, so reading your error

2 were given

When you call a class function, the instance of that class is always supplied as a parameter

example

class Foo:
  def bar(self, other=None):  # self is a required argument for instance methods
    pass

xyz = 'something'
booking = Foo()
booking.bar()  # 1 parameter provided - the instance itself
booking.bar(xyz)  # 2 parameters provided - the instance and the string

So, to fix your function, you need to add the self parameter, even if you don't plan on using it.

Before, the path variable you used wasn't actually a string, so the type checker should have been throwing an error as well

class Booking():
  def read_csv(self, path:str = None) -> List[List]:
    # TODO
    return []