[英]Sql in bash script (postgres)
i have a command in bash script for rename base.我在 bash 脚本中有一个用于重命名 base 的命令。 It's work, example这是工作,例子
psql -U $User -t -A -q -c 'ALTER DATABASE "Old_Name" RENAME TO "New_Name"' psql -U $User -t -A -q -c 'ALTER DATABASE "Old_Name" RENAME TO "New_Name"'
But if i do this -但如果我这样做 -
O_Name='Old_Name' O_Name='Old_Name'
N_Name='New_Name' N_Name='New_Name'
psql -U $User -t -A -q -c 'ALTER DATABASE "$O_Name" RENAME TO "$N_Name"' psql -U $User -t -A -q -c 'ALTER DATABASE "$O_Name" RENAME TO "$N_Name"'
It's not work, i think sql get $O_Name not Old_Name.这是行不通的,我认为 sql 得到的是 $O_Name 而不是 Old_Name。 How to pass the value of a variable bash to sql?如何将变量bash的值传递给sql?
Single quotes don't allow for environment variable expansion.单引号不允许环境变量扩展。 Use double quotes instead (and escape the nested quotes).改用双引号(并转义嵌套的引号)。 Like,喜欢,
psql -U $User -t -A -q -c "ALTER DATABASE \"$O_Name\" RENAME TO \"$N_Name\""
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