xslt - 选择具有特定子节点的节点

Question

I have an xml:

<mynodes>
   <mynode>
     <element1>a</element1>
     <element2>b</element2>
   </mynode>
   <mynode>
     <element1>c</element1>
     <element2>d</element2>
   </mynode>
</mynodes>
<translation>
  <col>element2</col>
  <cont>d</cont>
</translation>

I need an xpath, which gives me the the element1 content of the same subnode.

I have tried different xpaths, always with error.

My idea was to:

<xsl:variable name="col" select="/translation/col" />
<xsl:variable name="cont" select="/translation/cont" />
<xsl:value-of select="/mynodes/mynode[./name()=$col and ./text()=$cont]/element1" />

I have tried many things. Any idea? I did not want to loop the structure, because the structure is quite big and there are several queries to do.

Answer 1

使用<xsl:value-of select="/mynodes/mynode[*[name()=$col and . = $cont]]/element1"/>

Answer 2

XSLT has a built-in key mechanism for resolving cross-references - and it would be best to use it, esp. if you have "several queries to do".

Here you could define the key as:

<xsl:key name="k1" match="*" use="concat(name(), '|', .) " />

and then call it from the context of translation as::

<xsl:value-of select="key('k1', concat($col, '|', $cont))/../element1"/>