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无法在页面上显示 api 数据?

[英]Having trouble displaying api data on the page?

Im making a project where I fetch an image of a recipe card from https://spoonacular.com and I want it displayed on my react.js app.我正在制作一个项目,我从https://spoonacular.com获取食谱卡的图像,我希望它显示在我的 react.js 应用程序上。 For some reason I can't get the API data from displaying on the page when I run it.出于某种原因,当我运行它时,我无法在页面上显示 API 数据。 Please help Im really stuck.请帮助我真的卡住了。 I keep getting the error that recipeList is undefined in Recipe.js but I thought it was defined?我不断收到 Recipe.js 中未定义 recipeList 的错误,但我认为它已定义?

This is my Home.js:这是我的 Home.js:

import React, { useEffect, useState } from "react";
import axios from "axios";
import Recipe from "../components/Recipes";

const URL = `https://api.spoonacular.com/recipes/716429/information?apiKey=${APIKey}&includeNutrition=false`;

function Home() {
  const [food, setFood] = useState();

  useEffect(() => {
    if (food) {
      axios
        .get(URL)
        .then(function (response) {
          const recipeList = response.data;
          setFood(recipeList);
        })
        .catch(function (error) {
          console.warn(error);
        });
    }
  }, [food]);

  return (
    <main>
      <Recipe recipeList={food} />
    </main>
  );
}

export default Home;

this is my Recipe.js这是我的 Recipe.js

import React from "react";

function Recipe({ recipeList }) {
  return (
    <div className="Recipe">
      <div>{recipeList.title}</div>
      <img src={recipeList.image} />
    </div>
  );
}

export default Recipe;

you need initializing empty你需要初始化为空

const [food, setFood] = useState({});

and in useEffect evaluate if food is empty并在 useEffect 中评估食物是否为空

 useEffect(() => {
   const getData=()=>{
      axios
        .get(URL)
        .then(function (response) {
          const {data} = response;
          setFood(data);
        })
        .catch(function (error) {
          console.warn(error);
        });
     }
    if(!food){ // validate if food is empthy to get data (food)
        getData()
     }
  }, []); // here is not necesary use food, because never happen anything with that variable

The response example can be seen here .可以在此处查看响应示例。

To call that using axios:使用 axios 调用它:

import React, { useEffect, useState } from "react";
import axios from "axios";
import Recipe from "../components/Recipes";

const URL = `https://api.spoonacular.com/recipes/716429/information?apiKey=${APIKey}&includeNutrition=false`;

function Home() {
    const [food, setFood] = useState({});

    useEffect(() => {
        // You can add any if-else statement here
        // but you can also do the fetch without it
        axios
            .get(URL)
            .then(function (response) {
                setFood(response.data);
            })
            .catch(function (error) {
                console.warn(error);
            });
    }, []);

    return (
        <main>
            <Recipe recipeList={food} />
        </main>
    );
}

export default Home;

And based on the response, your Recipe.js should working properly.根据响应,您的Recipe.js应该可以正常工作。

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