我需要打印行号以及用户提示的内容，怎么做？ 我尝试了以下代码，但它不起作用

Question

Even if the line number is more than the present content it has to display the line numbers for empty lines and then print the user input in the specified line number with the content.

    #!/bin/bash
    file2='file2.txt'
    echo -en "Enter the line number:"
    read line_number
    echo -en "Enter the name of the city:"
    read city_name 
    total= 0
    if [ "$line_number" > "$total" ]
    then
       awk -v  city_name="$city_name" -v line_no="$line_no" -F, {print 
       city_name} 1' "file2"
    fi

Answer 1

Use -lt/-gt instead of '</>'

>>> x=7
>>> y=99
>>> if [ $x < $y ] ; then echo "x < y"; else echo "x >= y" ; fi
x >= y

>>> if [[ $x -lt $y ]] ; then echo "x < y"; else echo "x >= y" ; fi
x < y

Or use double [[]]

>>> if [[ $x < $y ]] ; then echo "x < y"; else echo "x >= y" ; fi
x < y