PowerShell - 使用排序的对象数组打印 JSON 输出？

Question

How can I print a JSON output with sorted array of objects? My $result object must remain as it is, the order of "Good" or "Bad" doesn't matter, I'm trying to sort the objects in the arrays sorted by "count" property in ascending order.

My code:

$result = [PSCustomObject]@{
    Good = @() 
    Bad  = @()
}

$food = [PSCustomObject]@{
    name  = "Banana"
    count = 2
}

if ($food.count -gt 3) { $result.Good += $food }
else { $result.Bad += $food }

$sortGood = $result.Good | Sort-Object count
$sortBad = $result.Bad | Sort-Object count
Write-Output ($result | ConvertTo-Json)

My JSON output is:

{
    "Good": [
                {
                    "name": "Apple"
                    "count": 10
                },
                {
                    "name": "Lime"
                    "count": 5
                },
                {
                    "name": "Peach"
                    "count": 7
                }
            ],
    "Bad": [
                {
                    "name": "Banana"
                    "count": 2
                },
                {
                    "name": "Kiwi"
                    "count": 1
                },
                {
                    "name": "Orange"
                    "count": 3
                }
            ] 
}

How can I print a JSON that looks like this? (fruits sorted by "count" property in ascending order)

{
    "Good": [
                {
                    "name": "Lime"
                    "count": 5
                },
                {
                    "name": "Peach"
                    "count": 7
                },
                {
                    "name": "Apple"
                    "count": 10
                },
            ],
    "Bad": [
                {
                    "name": "Kiwi"
                    "count": 1
                },
                {
                    "name": "Banana"
                    "count": 2
                },
                {
                    "name": "Orange"
                    "count": 3
                }
            ] 
}

[Problem fixed] Edited solution:

$result.Good = $result.Good | Sort-Object count
$result.Bad  = $result.Bad | Sort-Object count
Write-Output ($result | ConvertTo-Json)

Answer 1

Sort-Object does not "sort the object". It returns a sorted copy of the object. So this

$sortGood = $result.Good | Sort-Object count

will result in $sortGood being sorted properly, and $result.Good being exactly as it was.

$json = @"
{
    "Good": [
        {"name": "Apple", "count": 10},
        {"name": "Lime", "count": 5},
        {"name": "Peach", "count": 7}
    ],
    "Bad": [
        {"name": "Kiwi", "count": 1},
        {"name": "Orange", "count": 4}
    ] 
}
"@

$data = ConvertFrom-Json $json

$food = @{
    name  = "Banana"
    count = 2
}

if ($food.count -gt 3) {
    $data.Good += $food
} else {
    $data.Bad += $food
}

$data.Good = $data.Good | Sort-Object count
$data.Bad = $data.Bad | Sort-Object count

$result = $data | ConvertTo-Json -Depth 10
$result

gives

{
    "Good":  [
                 {
                     "name":  "Lime",
                     "count":  5
                 },
                 {
                     "name":  "Peach",
                     "count":  7
                 },
                 {
                     "name":  "Apple",
                     "count":  10
                 }
             ],
    "Bad":  [
                {
                    "name":  "Kiwi",
                    "count":  1
                },
                {
                    "count":  2,
                    "name":  "Banana"
                },
                {
                    "name":  "Orange",
                    "count":  4
                }
            ]
}

Note that I'm always re-assigning the values of $data.Good and $data.Bad :

• Using $data.Good += $food creates a new array (!) with $food at the end, and then assigns that to $data.Good . (It's shorthand for $data.Good = $data.Good + $food .)
• Using $data.Good = $data.Good | Sort-Object count $data.Good = $data.Good | Sort-Object count creates a new array (!) in a different order, and then assigns that to $data.Good .

Answer 2

Hey there I guess you forgot to add -Property after Sort-Object ie

$sortGood = $result.Good | Sort-Object -Property count

Give it a try and let me know !!!

Answer 3

I would do it like this:

ConvertTo-Json @{
    Good = $result.Good | sort Count
    Bad = $result.Bad | sort Count
}