在 C++ 中使用十六进制进行位掩码

Question

I need to mask my output in binary with hexadecimals variables. Do I need to convert the binary output to hexadecimal (or hexadecimals variables to binary)? Or is there any way in C++ to directly mask them and store it to a new variable?

#Edit : The binary output is stored to a std::bitset variable.

Answer 1

The use of bitset wasn't mentioned in your question, improve on that next time. You need to create a bitmask for the hex value as well. Then you can just & the bitmasks

#include <bitset>
#include <iostream>

int main()
{
    std::bitset<8> value{ 0x03 };
    std::bitset<8> mask{ 0x01 };
    std::bitset<8> masked_value = value & mask;

    std::cout << value.to_string() << " & " << mask.to_string() << " = " << masked_value.to_string() << "\n";
}