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基于不同列的可变窗口的熊猫滚动平均值

[英]Pandas rolling mean with variable window based on an different column

I would like to perform the rolling mean on a window that varies depending on the values of a column in my DataFrame.我想在一个窗口上执行滚动平均值,该窗口根据我的 DataFrame 中列的值而变化。 Can anyone help me?谁能帮我? Here is a starting point:这是一个起点:

import pandas as pd
import numpy as np

rng = np.random.default_rng()
df = pd.DataFrame(rng.integers(0, 100, size=(100, 2)), columns=list('AB'))
df.loc[:,'B']=df['B']//10

Now I would like to get the rolling mean of the series df.A with the window based on column B. For example if df.B[0] is worth 3 my_series[0]=df.A.rolling(3).mean()[0] and so on for my_series[1] etc...现在我想通过基于 B 列的窗口获得df.A系列的滚动平均值。例如,如果df.B[0]值 3 my_series[0]=df.A.rolling(3).mean()[0]等等my_series[1]等等...

Can you help me?你能帮助我吗? ty for your time I appreciate it.我很感激你的时间。

One option is to loop through the data frame, and assign a new column equal to the rolling_mean for each row.一种选择是循环遍历数据框,并为每一行分配一个等于rolling_mean 的新列。

df['rolling_mean'] = np.nan
for ind in range(len(df)):
    df.loc[df.index[ind], 'rolling_mean'] = df.A.rolling(df.loc[df.index[ind], 'B']).mean()[ind]

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