结构指针未按预期保存字符数组

Question

typedef struct _Text { 
  char *str; 
  int length; 
  int counter; 
  } *Text;


int main(void) {
  Text txt= malloc(sizeof(Text));
  char *txtStr="hi";
  txt->str=txtStr;
  return 0;
}

The struct simply doesn't work as expected, the char array given is not saved properly when checked.

Answer 1

typedef struct Text { 
  char *str; 
  int length; 
  int counter; 
  } Text;

is better to read

and then

int main(void) {
  Text *txt = malloc( sizeof( Text ));
  
  txt->str = malloc( sizeof( char ) *3);
  strcpy( txt->str, "hi" );

  printf("%s\n", txt->str );
  
  return 0;
}

Answer 2

Also in the UPV? I recognize this typedef because I am also struggling with tomorrow's assignment. I asked Oscar and he told me that you need to memory allocate space for the structure within the constructor of the class. He even provide me with some example code, yet I haven't managed to make it work yet.