如何在不使用向量的情况下调整动态指针数组的大小

Question

If I wanted to resize this array:如果我想调整这个数组的大小：

int array[5];

I would do this:我会这样做：

int* temp = new int [n];
...
array = temp;

But, how would I do it if I have this array?但是，如果我有这个数组，我该怎么做？

int *array[5];

Maybe like this?也许像这样？

int** temp = new int* [n];

Answer 1

You CAN'T resize a fixed array, period.您不能调整固定数组的大小，句点。 Its size is constant, determined at compile-time.它的大小是恒定的，在编译时确定。

You CAN'T assign a new[] 'ed pointer to a fixed array, either.不能将分配new[] “编指针到一个固定的阵列，无论是。

So, neither of your examples will work.所以，你的例子都不起作用。

In your 1st example, you would need this instead:在你的第一个例子中，你需要这个：

int* array = new int [5];

And in your 2nd example, you would need this instead:在你的第二个例子中，你需要这个：

int** array = new int* [5];

Either way, don't forget to delete[] the array before assigning something new to it, eg:无论哪种方式，在为array分配新内容之前不要忘记delete[] array ，例如：

int* array = new int [5];
...
int* temp = new int [n];
...
delete[] array;
array = temp;