[英]How does Ruby's to_s(2) translate into python?
So I've been trying to rewrite a Ruby snippet of code into Python, and I haven't been able to make it work.所以我一直在尝试将一段 Ruby 代码改写成 Python,但我一直无法让它工作。 I reread everything to make sure I did it right, but it still doesn't work.
我重新阅读了所有内容以确保我做对了,但它仍然不起作用。 I guess the problem lies in this "translation":
我想问题在于这个“翻译”:
def multiply(k, point = $G)
current = point
binary = k.to_s(2)
binary.split("").drop(1).each do |char|
current = double(current)
current = add(current, point) if char == "1"
end
current
end
This is my translated python version:这是我翻译的python版本:
def multiply(k, point = G):
current = point
binary = bin(k)
for i in binary[3:]:
current = double(current)
if i == "1":
current = add(current, point)
return current
I believe I didn't quite understand Ruby's concepts of to_s(2) and/or .drop(1) .我相信我不太了解 Ruby 的to_s(2)和/或.drop(1) 概念。 Could someone tell me what is the best way of translating this Ruby code into Python?
有人能告诉我将这个 Ruby 代码翻译成 Python 的最佳方法是什么吗?
EDIT So, I'll elaborate just as @Michael Butscher suggested:编辑因此,我将按照@Michael Butscher 的建议进行详细说明:
I have this Ruby code, which I tried to translate into this Python code.我有这个Ruby 代码,我试图将其翻译成这个Python 代码。 And while the output should be
虽然输出应该是
044aeaf55040fa16de37303d13ca1dde85f4ca9baa36e2963a27a1c0c1165fe2b11511a626b232de4ed05b204bd9eccaf1b79f5752e14dd1e847aa2f4db6a5
it throws an error.它抛出一个错误。 Why?
为什么?
The problem is not in the function you have shown, but in your inverse
function.问题不在于您显示的函数,而在于您的
inverse
函数。 /
between integers in Ruby translates as //
in Python 3: /
在 Ruby 中的整数之间转换为//
在 Python 3 中:
Ruby:红宝石:
3 / 2
# => 1
3.0 / 2
# => 1.5
Python 3:蟒蛇3:
3 / 2
# => 1.5
3 // 2
# => 1
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