在本机反应中：如何关闭下拉菜单视图，在功能组件内单击此下拉菜单外的屏幕
[英]In react-native: How to dismiss dropdown menu View, on clicking screen outside of this dropdown menu inside functional component
问题描述
I uses functional component to create below dropdown View, which I want to dismiss it on clicking anywhere in screen outside of this View.
我使用功能组件创建下拉视图，我想在单击此视图之外的屏幕中的任意位置时将其关闭。
1 个解决方案
解决方案1
0 2021-10-27 08:05:30
use this package使用这个包
react-native-element-dropdown here is the link react-native-element-dropdown 这里是链接
https://www.npmjs.com/package/react-native-element-dropdown https://www.npmjs.com/package/react-native-element-dropdown
I'm also using this package, a small video is also below.我也在用这个包，下面还有一个小视频。
https://drive.google.com/file/d/1b_QREC4JiMI5YCwFHPLsnraSoqvDrJ5C/view https://drive.google.com/file/d/1b_QREC4JiMI5YCwFHPLsnraSoqvDrJ5C/view
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