你如何从python中的函数返回多个变量

Question

I am creating a game that is played in the terminal and I wanted to reduce the amount of repetitive code by using functions eg

def p1_end_turn(p1_turn, p2_turn):
    p1_turn = False
    p2_turn= True
    return p1_turn, p2_turn

however when running the program with the code p1_end_turn(p1_turn, p2_turn) the variable p1_turn and p2_turn have not been changed. How can I make this code properly return the variables (im using python3.9.1 and have checked that the function works properly)

Answer 1

Returning a variable doesn't change the value of the variables. I think reading this page about variable scope and this page about immutable and mutable variables would be helpful.
As it has mentioned in second link, boolean variables are immutable objects.
If you really want to stick to your current code (which i highly recommend to first read links and decide what to do!), you can use something like this to change turns:

def change_trun(p1_turn, p2_turn):
    return not p1_turn, not p2_turn

# some codes
p1_turn, p2_turn = change_turn(p1_turn, p2_turn)

Last line is the key. variables should update with returned values.

Answer 2

Have a look at variable scopes (and possibly at mutable/immutable objects ). In short you only change p1_turn and p2_turn inside the function. This means that outside the function the values stay the same.

Answer 3

Your variables in the function are not the same as the ones out of it. Therefore you have to store the output in the variables you want.

def p1_end_turn(p1_turn, p2_turn):
    p1_turn = False
    p2_turn= True
    return p1_turn, p2_turn

P1_turn = True
P2_turn = True

P1_turn, P2_turn = p1_end_turn(P1_turn, P2_turn)