为什么我不能在同一个数组中推送索引？

Question

how can i push the index on one line like this->[1,2,2,3,2]
instead of this->[1][2][2][3][2]


 ``` let array = [1, [2, 3, [4, 5, ["six", "seven", 6666, [8, 9, [10]]]]]];```

function findLastElement (arr){
 for (let [index, element] of arr.entries()){
   if(typeof element === "object"){
    findLastElement(element)

1. i can't understand how to push index in the same array

   let array = [] array.push(index) console.log(array) } } } console.log(findLastElement(array))

2. my selution is- on first iteration i alredy have first index,how i can push the second one in the same array in console have only index like this [1,2,2,3,2]

Answer 1

Did you try the below? let arr = []; arr.push([1]); arr.push(2); arr.push([3]);

Answer 2

I think what's asked for is this. Please correct me if I'm wrong.

Given

const array = [1, [2, 3, [4, 5, ["six", "seven", 6666, [8, 9, [10]]]]]]

We can get these indices:

array .length //=> 2 ~~> last index = 1
array [2 - 1] .length //=> 3 ~~> last index = 2
array [2 - 1] [3 - 1] .length //=> 3 ~~> last index = 2 
array [2 - 1] [3 - 1] [3 - 1] .length //=> 4 ~~> last index = 3
array [2 - 1] [3 - 1] [3 - 1] [4 - 1] .length //=> 3 ~~>  last index = 2
array [2 - 1] [3 - 1] [3 - 1] [4 - 1] [3 - 1] .length //=> 1 ~~> last index = 0
array [2 - 1] [3 - 1] [3 - 1] [4 - 1] [3 - 1] [1 - 1] // not an array, so we're done

And so the sequence of indices we want is [1, 2, 2, 3, 2, 0] . This seems correct, but you original question did not include that final 0 , so perhaps I'm missing something important. In any case, here's a fairly simple recursion for that:

 const lastIndex = (x) => Array .isArray (x) ? [x .length - 1, ... lastIndex (x [x .length - 1])] : [] const array = [1, [2, 3, [4, 5, ["six", "seven", 6666, [8, 9, [10]]]]]] console .log (lastIndex (array))