当你到达句子中的某个字母时如何打破while循环

Question

I have this code I am writing and I am meant to break the while loop when the code reaches the letter 'd', but it isn't working. What did I do wrong? Also, at the end of the code I am meant o have the rest of the phrase showing and that is not working either.

word_input = 'How hard is this?'
stop_at_letter = 'd'
i = 0

print('While loop a')
while i < len(word_input):
    print(word_input[i])
    i = i + 1
    if i == stop_at_letter:
        break
else:
    print('Remaining letters are:' + str(word_input))

Answer 1

Instead of:

if i == stop_at_letter:

Do:

if word_input[i] == stop_at_letter

Note: when asking questions put your code directly to its body don't post pictures with it.

Answer 2

What you're doing at the moment in your code is comparing the variable 'i', which I assume you're using as a counter, to the character you want to stop at.

So you're basically comparing 0 to 'd', 1 to 'd'.. etc

Instead of doing that you want to use the index to get the right character in the string ( so word_input[i] ) and compare that with stop_at_letter.

Also, in order to get the remainder of the word, you can use slicing , which should basically look like word_input[i:len(word_input)] .

Answer 3

It's always a good idea to copy paste your code into your post instead of posting an image, so we have an easier time reproducing your problem.

word_input = 'How hard is this?!'

stop_letter = 'd'

result = []

for i in word_input:
    result.append(i)
    finalResult = ''.join(result)
    
    if i == stop_letter:
        break
    
print(finalResult)

Output:

How hard