如何在带空格和不带换行的 python 循环中打印

Question

i do not want new line in same output and want space between every two numbers the code :

num = [4 , 2]
for item in num:
   for i in range(item):
      print(item ,end="")

what I want :

4 4 4 4
2 2

what I get :

444422

Answer 1

Try this:

num = [4 , 2]
for item in num:
  for i in range(item):
    print(item, end=" ")
  print()

Edit:

I think it's overcomplicated for a problem like this, but you can try (it shouldn't print extra space at the end):

num = [4 , 2]
for item in num:
  for i in range(item):
    if item - 1 == i:
      print(item)
    else:
      print(item, end=" ")

It prints an item with a new line when it's the last number in the second loop otherwise it prints the number with a space.

Answer 2

You can use "\\n" which creates a new line as follow:

num = [4 , 2]
for item in num:
   for i in range(item):
      print(item, end=" ")
   print("\n")

Make sure the end has space in it; like " " instead of ""

Answer 3

num = [4 , 2]
for item in num:
    x = (str(item)+" ") * item
    x = x.rstrip()
    print(x,end="")        
    print()

Answer 4

Another approach with just 1 line of code inside for loop and not extra conditions:

num = [4 , 2]
for item in num:
    # [str(item)]*item creates a list with 'item' repeated 'item' no. of time.
    # Join this list with a space
    print (" ".join([str(item)]*item))

Output:

4 4 4 4
2 2