我如何摆脱括号？

Question

def name(reading):
    return reading
print(name([[10,9,9,10],2]))

When I get the program it prints [[10,9,9,10],2] but I need it to print without the extra brackets ending up with [10,9,9,10],2. I tried using things like (*reading, sep = ", ") but that only works when I use print directly. I ultimately want to know how to make reading = [10,9,9,10],2 and not [[10,9,9,10],2]. Thank you.

Answer 1

You can return it as a string using join()

def name(reading):
    return ",".join(str(x) for x in reading)

Answer 2

reading=[[10,9,9,10],2]
def name(reading):
    solution=""
    reading = [[10,9,9,10],2]
    for i in range(len(reading)):
        solution+=str(reading[i])
        if i<len(reading)-1:
            solution+=","
    return solution
print(name(reading))

How About this?

+and you should define reading in global scope.

Answer 3

You can use this:

def name(reading03=[[10,9,9,10],2]):
    reading02 = str(reading03)
    reading01 = reading02.replace("[", "")
    reading = reading01.replace("]", "")
    return reading
print(name)