在 bash shell 中以秒为单位获取当前时间的问题

Question

I need to retrieve the current time in seconds in a old machine (bash version 4.3) and this command is not working.

date +%s

It retrieves "%s" Any idea of what is wrong here?

Answer 1

现在，这对我有用：

nawk 'BEGIN {srand();time=srand();print time}' </dev/null

Answer 2

Try with printf function.

$ printf '%(%s)T' -1

1635846449