[英]How to get the values based on min and max date in groups in oracle?
I have a table having data like this:我有一个表,其中包含这样的数据:
Vehicle车辆 | Start开始 | End结尾 | Date日期 |
---|---|---|---|
Truck A卡车A | A一种 | B乙 | 02/01/2021 01:00:00 02/01/2021 01:00:00 |
Truck A卡车A | B乙 | C C | 02/01/2021 02:00:00 02/01/2021 02:00:00 |
Truck A卡车A | C C | D D | 04/01/2021 03:00:00 04/01/2021 03:00:00 |
Truck B卡车B | C C | A一种 | 05/01/2021 01:00:00 05/01/2021 01:00:00 |
Truck B卡车B | A一种 | B乙 | 06/01/2021 01:00:00 06/01/2021 01:00:00 |
Truck C卡车 C | C C | B乙 | 07/01/2021 01:00:00 07/01/2021 01:00:00 |
Truck C卡车 C | B乙 | C C | 08/01/2021 01:00:00 08/01/2021 01:00:00 |
Truck C卡车 C | C C | B乙 | 09/01/2021 01:00:00 09/01/2021 01:00:00 |
Truck C卡车 C | B乙 | A一种 | 10/01/2021 01:00:00 10/01/2021 01:00:00 |
I need to get the starting and ending point of each vehicle based on the date.我需要根据日期获取每辆车的起点和终点。
For example, Truck A has started from point A to point B on 02/01/2021 01:00:00.例如,卡车 A 在 02/01/2021 01:00:00 从 A 点出发到 B 点。 Then Truck A has moved from point B to point C on 02/01/2021 02:00:00.然后卡车 A 在 02/01/2021 02:00:00 从 B 点移动到 C 点。 Truck A has moved from point C to point D on 04/01/2021 03:00:00.卡车 A 已于 04/01/2021 03:00:00 从 C 点移动到 D 点。
It has started from point A and ended at point D.它从 A 点开始,在 D 点结束。
I want to get a result like this:我想得到这样的结果:
Vehicle车辆 | Start开始 | End结尾 | Date日期 |
---|---|---|---|
Truck A卡车A | A一种 | D D | 04/01/2021 03:00:00 04/01/2021 03:00:00 |
Use GROUP BY
and aggregate using KEEP
to get the FIRST
or LAST
date values:使用GROUP BY
并使用KEEP
聚合以获取FIRST
或LAST
日期值:
SELECT vehicle,
MIN("START") KEEP (DENSE_RANK FIRST ORDER BY "DATE") AS "START",
MAX("END") KEEP (DENSE_RANK LAST ORDER BY "DATE") AS "END",
MAX("DATE") AS "DATE"
FROM table_name
GROUP BY vehicle
Which, for the sample data:其中,对于样本数据:
CREATE TABLE table_name (Vehicle, "START", "END", "DATE") AS
SELECT 'Truck A', 'A', 'B', DATE '2021-01-02' + INTERVAL '1' HOUR FROM DUAL UNION ALL
SELECT 'Truck A', 'B', 'C', DATE '2021-01-02' + INTERVAL '2' HOUR FROM DUAL UNION ALL
SELECT 'Truck A', 'C', 'D', DATE '2021-01-04' + INTERVAL '3' HOUR FROM DUAL UNION ALL
SELECT 'Truck B', 'C', 'A', DATE '2021-01-05' + INTERVAL '1' HOUR FROM DUAL UNION ALL
SELECT 'Truck B', 'A', 'B', DATE '2021-01-06' + INTERVAL '1' HOUR FROM DUAL UNION ALL
SELECT 'Truck C', 'C', 'B', DATE '2021-01-07' + INTERVAL '1' HOUR FROM DUAL UNION ALL
SELECT 'Truck C', 'B', 'C', DATE '2021-01-08' + INTERVAL '1' HOUR FROM DUAL UNION ALL
SELECT 'Truck C', 'C', 'B', DATE '2021-01-09' + INTERVAL '1' HOUR FROM DUAL UNION ALL
SELECT 'Truck C', 'B', 'A', DATE '2021-01-10' + INTERVAL '1' HOUR FROM DUAL
Outputs:输出:
VEHICLE车辆 START开始 END结尾 DATE日期 Truck A卡车A A一种 D D 2021-01-04 03:00:00 2021-01-04 03:00:00 Truck B卡车B C C B乙 2021-01-06 01:00:00 2021-01-06 01:00:00 Truck C卡车 C C C A一种 2021-01-10 01:00:00 2021-01-10 01:00:00
WITH CTE(Vehicle, StartT, EndD, DateD) AS
(
SELECT 'Truck A', 'A' ,'B', CAST('02/01/2021 01:00:00'AS SMALLDATETIME) UNION ALL
SELECT'Truck A' , 'B', 'C', CAST('02/01/2021 02:00:00'AS SMALLDATETIME) UNION ALL
SELECT'Truck A', 'C' , 'D', '04/01/2021 03:00:00' UNION ALL
SELECT'Truck B', 'C' , 'A', '05/01/2021 01:00:00' UNION ALL
SELECT'Truck B', 'A', 'B', '06/01/2021 01:00:00' UNION ALL
SELECT'Truck C', 'C' , 'B', '07/01/2021 01:00:00' UNION ALL
SELECT'Truck C' , 'B', 'C', '08/01/2021 01:00:00' UNION ALL
SELECT'Truck C' , 'C' , 'B', '09/01/2021 01:00:00' UNION ALL
SELECT'Truck C' , 'B', 'A', '10/01/2021 01:00:00'
),
CTE2(Vehicle, StartT, EndD, DateD,XCOL,YCOL) AS
(
SELECT C.Vehicle,C.STARTT,C.ENDD,C.DATED,
ROW_NUMBER()OVER(PARTITION BY C.Vehicle ORDER BY C.DATED ASC)XCOL,
ROW_NUMBER()OVER(PARTITION BY C.Vehicle ORDER BY C.DATED DESC)YCOL
FROM CTE AS C
)
SELECT C.VEHICLE,C.StartT,X.EndD,X.DateD
FROM CTE2 AS C
JOIN CTE2 AS X ON C.Vehicle=X.Vehicle
WHERE C.XCOL=1 AND X.YCOL=1
Sorry, I don't have Oracle, so have created the query for MS SQL Server CTE represents your sample data CTE2 calculates "bidirectional" row_number.抱歉,我没有 Oracle,因此创建了 MS SQL Server CTE 查询表示您的示例数据 CTE2 计算“双向”row_number。 For start row(eg for 'TruckA') XCOL=1.对于起始行(例如对于 'TruckA')XCOL=1。 For end row YCOL=1 Then we join these two CTEs on Vehicle.对于 end row YCOL=1 然后我们在 Vehicle 上加入这两个 CTE。 Could you please try this query if it is suitable for you你能试试这个查询是否适合你
I think this solution should work for you, although probably there is a more elegant solution.我认为这个解决方案应该适合你,尽管可能有一个更优雅的解决方案。
with x ( Vehicle , Start_Letter ,End_Letter , Date_Letter )
as
(
select 'Truck A' , 'A' , 'B' , to_date('02/01/2021 01:00:00','dd/mm/yyyy hh24:mi:ss') from dual union all
select 'Truck A' , 'B' , 'C' , to_date('02/01/2021 02:00:00','dd/mm/yyyy hh24:mi:ss') from dual union all
select 'Truck A' , 'C' , 'D' , to_date('04/01/2021 03:00:00','dd/mm/yyyy hh24:mi:ss') from dual union all
select 'Truck B' , 'C' , 'A' , to_date('05/01/2021 01:00:00','dd/mm/yyyy hh24:mi:ss') from dual union all
select 'Truck B' , 'A' , 'B' , to_date('06/01/2021 01:00:00','dd/mm/yyyy hh24:mi:ss') from dual union all
select 'Truck C' , 'C' , 'B' , to_date('07/01/2021 01:00:00','dd/mm/yyyy hh24:mi:ss') from dual union all
select 'Truck C' , 'B' , 'C' , to_date('08/01/2021 01:00:00','dd/mm/yyyy hh24:mi:ss') from dual union all
select 'Truck C' , 'C' , 'B' , to_date('09/01/2021 01:00:00','dd/mm/yyyy hh24:mi:ss') from dual union all
select 'Truck C' , 'B' , 'A' , to_date('10/01/2021 01:00:00','dd/mm/yyyy hh24:mi:ss') from dual
)
select vehicle , start_letter, end_letter, date_letter from
(
select vehicle , min_start_lett as start_letter, max_start_lett as end_letter, date_letter,
row_number() over(partition by vehicle order by date_letter desc) as ranking
from
(
select x.* ,
rank() over(partition by vehicle order by start_letter desc, end_letter desc, date_letter desc ) as rn ,
min(start_letter) over(partition by vehicle) as min_start_lett ,
max(end_letter) over(partition by vehicle) as max_start_lett
from x
) d
where rn = ( select max(rn) from x c where c.vehicle = d.vehicle group by vehicle )
) where ranking = 1
;
Using the window function FIRST_VALUE to find the first and last for each vehicle使用窗函数 FIRST_VALUE 查找每辆车的第一个和最后一个
SELECT Vehicle
, FirstStart AS "Start"
, LastEnd AS "End"
, MAX("Date") AS "Date"
FROM
(
SELECT Vehicle, "Start", "End", "Date"
, FIRST_VALUE("Start") OVER (PARTITION BY Vehicle ORDER BY "Date") AS FirstStart
, FIRST_VALUE("End") OVER (PARTITION BY Vehicle ORDER BY "Date" DESC) AS LastEnd
FROM yourtable
) q
GROUP BY Vehicle, FirstStart, LastEnd
ORDER BY Vehicle;
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