如何从元组列表创建数据框？

Question

I have the following list of tuples:

q1 =[('energy level has been raised', 3317,
[{'ResultId': 1, 'CompletedOn': '2021-01-07T10:35:18.29+01:00', 'EnteredValue': None, 'EnteredOn': '2021-11-03T13:22:48.91+01:00', 'TextValue': None},
{'ResultId': 2, 'CompletedOn': '2021-01-07T10:38:19.12+01:00', 'EnteredValue': None, 'EnteredOn': '2021-11-03T13:28:11.267+01:00', 'TextValue': None}, 
{'ResultId': 3, 'CompletedOn': '2021-11-03T13:09:19.333+01:00', 'EnteredValue': None, 'EnteredOn': '2021-11-03T13:09:19.333+01:00', 'TextValue': None},
{'ResultId': 4, 'CompletedOn': None, 'EnteredValue': None, 'EnteredOn': None, 'TextValue': None},
{'ResultId': 5, 'CompletedOn': None, 'EnteredValue': None, 'EnteredOn': None, 'TextValue': None}, 
{'ResultId': 6, 'CompletedOn': None, 'EnteredValue': None, 'EnteredOn': None, 'TextValue': None}, 
{'ResultId': 7, 'CompletedOn': None, 'EnteredValue': None, 'EnteredOn': None, 'TextValue': None}],
'energy level has fallen down'),
({'code': '', 'message': 'Exception LS-27186:01 (4411459)'},)]

I'm trying to create a dataframe of above data but the problem is that the second tuple inside q1 does not have a tup[2]. So i need to find a way to ignore the tuples that dont have the same layout as the first one...

when I run below code I get the following error:

df1 = pd.DataFrame.from_records([create_record(record)for tup in q1 for record in tup[2]])
IndexError: tuple index out of range

This is my code:

def create_record(record):
    pd_record = {
        'ResultID': record['ResultId'],
                }     

df1 = pd.DataFrame.from_records([create_record(record)for tup in q1 for record in tup[2]])

print(df1.head)

Answer 1

Try:

def create_record(record):
    pd_record = {'ResultID': record['ResultId']}
    return pd_record


df1 = pd.DataFrame.from_records([create_record(record) for tup in q1 if len(tup) > 1 for record in tup[2]])
print(df1)

Output

   ResultID
0         1
1         2
2         3
3         4
4         5
5         6
6         7