对于这个 if/else 语句，JavaScript 条件运算符是更好的方法吗？

Question

I am trying to see if I can reduce the code below with less JavaScript. When the user select Even dropdown option the only differences between that and the else statement is "i = 0" and "i % 2 === 0"

any recommendations? Maybe conditional operator would be best method? thank you

        if (this.selection == "even") {
            for (let i = 0; i <= number; i++) {
                if (i % 2 === 0) 
                this.results.push(i + "\n");
            }
        } else {
            for (let i = 1; i <= number; i++) {
                if (i % 2 !== 0) 
                this.results.push(i + "\n");
            }
        }

Answer 1

Use this.selection to determine the starting number, then increment by 2 inside the loop instead of i++ , so you don't have to check i % 2 .

const startAt = this.selection == "even" ? 0 : 1;
for (let i = startAt; i <= number; i += 2) {
    this.results.push(i + "\n");
}