将文件读入二维数组

Question

I'm new in C and trying to put a text file into a 2D array. For example: Text file content: When, in the course of human events, it becomes necessary dark like To put it in the 2D array like this: when, in the course ...

However, it works fine for the first word, which is "when,", is stored in the 2D array then the rest is just like in the picture.

enter image description here

Could you help me to figure out what went wrong please? Here is my code:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <time.h>
#include <ctype.h>
#define SIZE 100
#define ROWS 5000
#define COLS 50

int readFile(char text[ROWS][COLS]);
void menu(char* choice);

int main() {
    int numWords = 0,valid,readFileFirst = 0,i;
    char *text,choice;
    text = (char*)malloc((ROWS*COLS)*sizeof(char));
    numWords = readFile(text);
}

int readFile(char text[][COLS]) {
FILE *keyFile;
char fileInput[SIZE],inBuf[SIZE],ch;
int i = 0, j = 0;
int numWords = 1;
int valid = 0;

printf("Enter the file to use as a key\n");
fgets(inBuf,SIZE,stdin);
sscanf(inBuf,"%s",fileInput);

keyFile = fopen(fileInput,"r");

if(keyFile == NULL) {
    printf("Error! Find Not Found");
}

else {
    while((ch = fgetc(keyFile)) != EOF) {
        if(ch == ' ' || ch == '\n' || ch == '\r' || ch == '\0') {
            numWords++;
            i++;
            j = 0;
        }
        
        else {
            text[i][j] = tolower((unsigned char)ch);
            j++;
        }
    }
}

printf("Number of words in this file is %d\n", numWords);
printf("%c\n", text[2][1]);
return numWords;
}

Answer 1

1. solution:

change

char*text;

text = (char*)malloc((ROWS*COLS)*sizeof(char));

to

char text[COLS][ROWS];

2. solution

if you want to use malloc() you need a pointer char **ptr which is a pointer to a char *pointer wich points to char

char **text = malloc( COLS * sizeof(char*));
for( int i = 0; i < COLS; ++i )
{
  text[i] = malloc( ROWS * sizeof( char ));
}