[英]bash: How to replace an entire line in a text file by a part of its content
I have a text file, called texto.txt in Documentos folder, with some values like the ones below:我在 Documentos 文件夹中有一个名为 texto.txt 的文本文件,其中包含一些如下所示的值:
cat ~/Documentos/texto.txt
65f8: Testado
a4a1: Testado 2
So I want to change a whole line by using a customized function which gets as parameters the new value.所以我想通过使用自定义函数来更改整行,该函数获取新值作为参数。 The new value will always keep the first 6 characters, changing only what comes after them.
新值将始终保留前 6 个字符,仅更改它们之后的字符。 Although I am testing only the first four.
虽然我只测试前四个。
Then I edited my .bashrc including my function like shown below.然后我编辑了我的 .bashrc,包括我的函数,如下所示。
muda()
{
export BUSCA="$(echo $* | cut -c 1-4)";
sed -i "/^$BUSCA/s/.*/$*/" ~/Documentos/texto.txt ;}
When I run the command below it works like a charm, but I feel it could be improved.当我运行下面的命令时,它就像一个魅力,但我觉得它可以改进。
muda a4a1: Testado 3
Result:结果:
cat ~/Documentos/texto.txt
65f8: Testado
a4a1: Testado 3
Is there a smarter way to do this?有没有更聪明的方法来做到这一点? Maybe by getting rid of BUSCA variable?
也许通过摆脱 BUSCA 变量?
I'd write:我会写:
muda() {
local new_line="$*"
local key=${newline:0:4}
sed -i "s/^${key//\//\\/}.*/${new_line//\//\\/}/" ~/Documentos/texto.txt
}
Notes:笔记:
local
variables, not exported environment variableslocal
变量,而不是导出的环境变量
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