比较python中两个列表索引的方法

Question

list1=['name1','name2','name3']
list2=[123,1234,12345]

i wanna say in python if index of 'name1'in the first list is equal to index of 123 in the second list without knowing them for example 'name1' and 123 is user input

i have tried many things like using .index but i get an error TypeError: list indices must be integers or slices, not str TypeError: list indices must be integers or slices, not str

and tried many other things but none worked as i wanted

Answer 1

You can do the following:

list1 = ['name1', 'name2', 'name3']
list2 = [123, 1234, 12345]

name = input("name: ")
num = int(input("num: "))  # don't forget to convert to int

if (name, num) in zip(list1, list2):
    print("Yay")
else:
    print("Aww")

Answer 2

Assuming they are the same length

for count, data in enumerate(list1):
    if(list1[count] == list2[count]):
        print("yay")

If you just want to know if both lists contain the same data

for count, data in enumerate(list1):
    if(data in list2):
        print("yay")