检查字典值中是否存在列表元素

Question

I have a list and a dictionary, and I need to check if elements of the list exist in the dictionary. If yes, I need to copy the key-value pair to a new dictionary, and discard the rest from the dictionary.

list0 = [
    -0.2385384148158066,
    -0.2307061452151448,
    -0.2150726345799602,
    -0.2138622652947372,
    -0.1098235264547504,
    -0.1072424768342444,
    -0.1037212327115436,
    -0.0966926943378552,
    -0.09614853460521154,
    9.353161396230564e-07
]
dict0 = {
    67: 1.440192237446893e-05,
    91: -0.1037212327115436,
    115: -0.2307061452151448,
    172: 0.0002879308975510175,
    242: 1.340170610273099e-05,
    266: -0.09614853460521154,
    290: -0.2138622652947372,
    347: 9.353161396230564e-07,
    417: 1.462739691486375e-05,
    441: -0.1072424768342444,
    465: -0.2385384148158066,
    513: 0.001208308075300354,
    606: -0.1098235264547504,
    630: -0.2442794187837403,
    677: 0.0007379497093922571,
    747: 1.336163063745514e-05,
    771: -0.0966926943378552,
    794: -0.2150726345799602
}

I tried iterating over the list and checking if the element is in dict0.values() and vice versa, but still couldn't figure out any way to access both key and value.

Answer 1

You can use a dict comprehension:

>>> {k: v for k, v in dict0.items() if v in list0}
{91: -0.1037212327115436, 115: -0.2307061452151448, 266: -0.09614853460521154, 290: -0.2138622652947372, 347: 9.353161396230564e-07, 441: -0.1072424768342444, 465: -0.2385384148158066, 606: -0.1098235264547504, 771: -0.0966926943378552, 794: -0.2150726345799602}

If your list0 is very big, converting it to a set makes the above method faster:

>>> set0 = set(list0)
>>> {k: v for k, v in dict0.items() if v in set0}

Answer 2

Thats Pretty Simple to do:

This snippet may help:

new_dict={}
    for item in list0:
       for d in dict0:
          if(item==dict0[d]):
             new_dict[d]=item

Answer 3

I'm not able to figure out why didn't you get the answer by iteration. You've not pasted your code, so I'm giving the answer in iteration method only so that you can compare it with your code. The code would be:

list0 = [
    -0.2385384148158066,
    -0.2307061452151448,
    -0.2150726345799602,
    -0.2138622652947372,
    -0.1098235264547504,
    -0.1072424768342444,
    -0.1037212327115436,
    -0.0966926943378552,
    -0.09614853460521154,
    9.353161396230564e-07
]
dict0 = {
    67: 1.440192237446893e-05,
    91: -0.1037212327115436,
    115: -0.2307061452151448,
    172: 0.0002879308975510175,
    242: 1.340170610273099e-05,
    266: -0.09614853460521154,
    290: -0.2138622652947372,
    347: 9.353161396230564e-07,
    417: 1.462739691486375e-05,
    441: -0.1072424768342444,
    465: -0.2385384148158066,
    513: 0.001208308075300354,
    606: -0.1098235264547504,
    630: -0.2442794187837403,
    677: 0.0007379497093922571,
    747: 1.336163063745514e-05,
    771: -0.0966926943378552,
    794: -0.2150726345799602
}
new_dict={}
for i in dict0:
    if dict0[i] in list0:
        new_dict[i]=dict0[i]
print(new_dict)