是否可以通过稍加修改从另一个规范生成 Openapi 规范文件？

Question

Suppose I have Openapi specification file (api-docs.yml). I need to create a copy of it with:

1. different servers block
2. filtered paths by tag (with removing unnecessary schemas)

Do any solutions exist to make such things, or it's only possible to write your own parser?

I'm using Java so Java-based solutions (maven plugins etc.) are preferred.

Answer 1

Do any solutions exist to make such things, or it's only possible to write your own parser?

There are OpenAPI parsers for various programming languages. In Java, you can use Swagger Parser - use version 2.x for OpenAPI 3.0.x or v. 1.x for OpenAPI 2.0 ( swagger: '2.0' ).

I think openapi-filter can filter content by tags, among other things.

You can also try using a YAML parser/processor such as yq .